+ /i#B^RIHtHtHtHtHtHt^RIHtR.t RRlt R#))zerosasarrayeyepoly1dhstackr_)linalgpadeNcH\V4pVf,\V4^, V, pV^8d \R4hV^8d \R4hW,pV\V4^, 8d \R4hVRV^,p\V^,V^,VPR7p\ V^,V3VPR7p\ ^V^,4FpVRVRRR1,)WVRV13&K \ V^,V^,4FpWV, VRRR1,)WVR3&K \WE34p\P!Wp4pVRV^,p \RW^,R3,p \V RRR1,4\V RRR1,43#) a5 Return Pade approximation to a polynomial as the ratio of two polynomials. Parameters ---------- an : (N,) array_like Taylor series coefficients. m : int The order of the returned approximating polynomial `q`. n : int, optional The order of the returned approximating polynomial `p`. By default, the order is ``len(an)-1-m``. Returns ------- p, q : Polynomial class The Pade approximation of the polynomial defined by `an` is ``p(x)/q(x)``. Examples -------- >>> import numpy as np >>> from scipy.interpolate import pade >>> e_exp = [1.0, 1.0, 1.0/2.0, 1.0/6.0, 1.0/24.0, 1.0/120.0] >>> p, q = pade(e_exp, 2) >>> e_exp.reverse() >>> e_poly = np.poly1d(e_exp) Compare ``e_poly(x)`` and the Pade approximation ``p(x)/q(x)`` >>> e_poly(1) 2.7166666666666668 >>> p(1)/q(1) 2.7179487179487181 Nz.Order of q must be smaller than len(an)-1.z&Order of p must be greater than 0.z0Order of q+p must be smaller than len(an).)dtype:NNNg?) rlen ValueErrorrr rrangerr solverr) anmnNAkjBkjrowCpqpqs &&& U/var/www/html/photoedit/myenv/lib/python3.14/site-packages/scipy/interpolate/_pade.pyr r s{N By GaK!O q5MN N1uABB A3r719}KLL DQqSB ac1Q3bhh 'C 1a )CQ!}Tc(DbD))H QqS!A#a%}dd++E zA a B 4AaCA 3Q34=A !DbD'?F1TrT7O ++)N) numpyrrrrrrscipyr __all__r rrr#s99 (<,r